What is the taylor series expansion for the tangent function (tanx ...
2018年5月22日 · tan x = x + 1/3x^3 +2/15x^5 + ... The Maclaurin series is given by f(x) = f(0) + (f'(0))/(1!)x + (f''(0))/(2!)x^2 + (f'''(0))/(3!)x^3 + ... (f^((n))(0))/(n!)x^n ...
Proving Identities - Trigonometry - Socratic
If tanx =3/4, π < x <3 π /2, find the values of sin (x/2), cos (x/2) and tan (x/2)? Question #07cd9.
What is the limit as x approaches 0 of tanx/x? | Socratic
2018年6月12日 · 1 lim_(x->0)tanx/x graph{(tanx)/x [-20.27, 20.28, -10.14, 10.13]} From the graph, you can see that as x->0, tanx/x approaches 1
Cscx * tanx? - Socratic
2018年6月7日 · secx definitions: csc=1/sin tan=sin/cos solve: =cscx * tanx =1/sinx*sinx/cosx =1/cancel(sinx)*cancel(sinx)/cosx =1/cosx =secx
What is the antiderivative of #tan(x)#? - Socratic
2014年10月16日 · Recall: int{g'(x)}/{g(x)}dx=ln|g(x)|+C (You can verify this by substitution u=g(x).) Now, let us look at the posted antiderivative. By the trig identity tan x={sin x}/{cos x}, int tan x …
How do you simplify secx/tanx? - Socratic
2016年11月13日 · Let's use the definitions of #secx# and #tanx# to simplify this. We know. #secx=1/cosx# and #tanx=sinx/cosx#.Let's plug these values into our original expression. we get
Cscx/cotx+tanx= cosx? - Socratic
2018年3月28日 · To prove the identity, you'll need these four, more basic identities: cscx=1/sinx cotx=cosx/sinx tanx=sinx/cosx sin^2x+cos^2x=1 To start the proof, use these identities to write …
How do you integrate (tan(x))/x? - Socratic
2016年11月4日 · I believe the only way to handle this integral is to use the Maclaurin power series for tanx; as follows ...
How do you integrate Sinx * Tanx? | Socratic
2016年12月9日 · The answer is =ln (∣tanx+secx∣)-sinx +C We need, secx=1/cosx cos^2x+sin^2x=1 tanx=sinx/cosx (tanx)'=sec^2x (secx)'=tanx secx …
Lim x->0 (tan x- sin x)/x^3=? - Socratic
2017年11月9日 · lim_(x->0) (tanx-sinx)/x^3 = 1/2 Transform the function in this way: (tanx-sinx)/x^3 = 1/x^3(sinx/cosx-sinx) (tanx-sinx)/x^3 = 1/x^3((sinx-sinxcosx)/cosx) (tanx-sinx ...